-3x^2+160x-1600=0

Solution for -3x^2+160x-1600=0 equation:

-3x^2+160x-1600=0

a = -3; b = 160; c = -1600;
Δ = b2-4ac
Δ = 1602-4·(-3)·(-1600)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(160)-80}{2*-3}=\frac{-240}{-6}
=+40
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(160)+80}{2*-3}=\frac{-80}{-6}
=13+1/3
$